4/5 rating based on 86 reviews. Read all reviews for pythoni-run code,autocomplete for iPhone.
pythoni-run code,autocomplete is free iOS app published by XiaoWen Huang
JohnnyYourmomic
Even if you’re a noobody like me, this is a very user maneuverable interface suite, and I’m grateful for the education and time spent on development
最近ゲームをしなかった人
When I call range with all its parameters; start, stop, step or with just the start and stop, it gives me a syntax error. That is, this works: range(16) This doesn’t work: range(0, 16) Nor does this: range(0, 16, 2) To help reproduce the bug, here is my source code. #I'm basically writing a Turing sandbox for the hell of it. I'll be writing an instruction set specification, then I'll come back here. #globals memory = [] for i in range(65536): #populating the memory array with 65KB of blank memory. memory.append(0) memWindow = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0] paramReg = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0] programCounter = 0 stackPointer = 65535 allocPointer = 65535 windowLoc = 65535 def main (): # getting the hex file for the program the user wants to run from the user. programStr = "" while True: print("myMachine Ver. 0.1 (incomplete)") progPath = raw_input("Please type the name of the program to be executed: ") try: progFile = open(progPath, "r") programStr = progFile.read() break except: print("The file " + progPath + " was not found.") # remove comments and line breaks from the hex code. Comments are allowed but must be on their own line. programStr = cleanHexCode(programStr) #Run through the hexcode, convert it to integers and load it into memory. loadMemory(programStr) print(memory) def loadMemory(sourceStr): if len(sourceStr) % 2 != 0: sourceStr = sourceStr + "0" print ("WARNING Odd number of digits.") memAddress = 0 for i in range(0,len(sourceStr),2): if memAddress >= len(memory): print("Program does not fit in memory!") exit() try: memory[memAddress] = int("0x" + sourceStr[i:i+2]) except: print ("Invalid hex code!") exit() memAddress += 1 def cleanHexCode (sourceStr): cleanCode = "" codeLines = sourceStr.split("\n") for i in codeLines: i = i.strip() if i[0] != '#': cleanCode = cleanCode + i return cleanCode if __name__ == "__main__": main() Here is the error it produces: File "<string>", line 44 for i in range(0,len(sourceStr),2): ^ SyntaxError: invalid syntax
wannabecoder
def main(): myfirstvarianble="hello world" print("hello world") print main() wont work. literally copied off of the youtube tutorial. works on his screen. not mine because it is garbage